x^2+2=(x-2)(x+4)

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Solution for x^2+2=(x-2)(x+4) equation: 



x^2+2=(x-2)(x+4)

We move all terms to the left:

x^2+2-((x-2)(x+4))=0

We multiply parentheses ..

x^2-((+x^2+4x-2x-8))+2=0



We calculate terms in parentheses: -((+x^2+4x-2x-8)), so:

(+x^2+4x-2x-8)

We get rid of parentheses

x^2+4x-2x-8

We add all the numbers together, and all the variables

x^2+2x-8

Back to the equation:

-(x^2+2x-8)



We get rid of parentheses

x^2-x^2-2x+8+2=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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